Match Info
CHALLENGER MEN - SINGLES: Buenos Aires 3 - Qualification, clay - Semi-finalsDate: 21 September 2026, Monday
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Federico Aguilar Cardozo |
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Ryan Dickerson |
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- The most likely Over/Under: 20.50
- The best margin for this event is 5.7%, offered by

#Advertisement. For Live Stream GEO restrictions apply. Funded account required. GamblingTherapy.org. 18+ Current Win Probability
Federico Aguilar Cardozo 75.8% | Ryan Dickerson 24.2% |
Initial Probability
(when we started the analysis)
Our Initial ML Estimation
Analysis of Changes in Winning Probabilities:
Federico Aguilar Cardozo has improved its chances compared to the initial analysis. (+16.1%)Note: This is a significant improvement in prediction, suggesting increased confidence in Federico Aguilar Cardozo's performance.Ryan Dickerson has seen a decrease in its chances compared to the initial analysis. (-16.1%)Note: This is a significant drop in prediction, and Ryan Dickerson might be facing challenges that affect their performance.ML Model estimates a lower probability for Federico Aguilar Cardozo than the current prediction. (-20.4%)Note: The ML model's lower estimate suggests that there may be underlying issues with Federico Aguilar Cardozo that the model has picked up on.ML Model estimates a higher probability for Ryan Dickerson than the current prediction. (+20.4%)Note: The ML model's higher estimate suggests that Ryan Dickerson could outperform expectations, possibly based on recent matchups or player stats.Federico Aguilar Cardozo - Ryan Dickerson Predictions
Expected Score (Market Odds): 2:0 
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Preview
Aguilar Cardozo is ranked ATP: 1057., and Dickerson is ranked ATP: 693..Aguilar Cardozo has experienced an up-and-down run in recent matches (last 5 matches: 3 wins).Dickerson is experiencing a dip in performance (last 5 matches: 1 win).Dickerson may face physical fatigue compared to their opponent, having played more matches in recent days. No recent head-to-head matches have been recorded between these two competitors.
Form
✺ - easy match;
✺ - difficult match;