Match Info
CHALLENGER MEN - SINGLES: Modena, clay - Quarter-finalsDate: 4 July 2025, Friday
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Federico Cina |
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Juan Manuel Cerundolo |
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- The best margin for this event is 3.6%, offered by

#Advertisement. For Live Stream GEO restrictions apply. Funded account required. GamblingTherapy.org. 18+ Current Win Probability
Federico Cina 36.4% | Juan Manuel Cerundolo 63.6% |
Initial Probability
(when we started the analysis)
Our Initial ML Estimation
Analysis of Changes in Winning Probabilities:
Federico Cina has improved its chances compared to the initial analysis. (+3.3%)Juan Manuel Cerundolo has seen a decrease in its chances compared to the initial analysis. (-3.3%)ML Model estimates a higher probability for Federico Cina than the current prediction. (+0.3%)ML Model estimates a lower probability for Juan Manuel Cerundolo than the current prediction. (-0.3%)Federico Cina - Juan Manuel Cerundolo Predictions
Users Predictions:
9 users predict this event. Cina will win (votes: 8 - 88.9%). Cerundolo will win (votes: 1 - 11.1%).
Confidence interval (95%) for Cina: 68.4% – 100%.Verified Performance Core (Selected Experts): Federico Cina will win (3 of 4 users predict this - 75%) 🥉 Bronze Tip.Expected Score (Market Odds): 0:2 
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Preview
Cina is ranked ATP: 279. Cerundolo is ranked ATP: 112.Cina is undoubtedly in great shape (last 5 games: 4 wins).Cerundolo has been playing with ups and downs recently (in the last 5 games, wins – 2).Cerundolo may have a physical advantage due to more rest days in recent times. Cerundolo is expected to have a slight advantage in this match.In the last 1 head-to-head match, Cina won 0 matches, drew 0 matches, lost 1 match, and goals 0:2.
Last Results with these Odds
Juan Manuel Cerundolo - the odds 1.39 are the expected chance of winning is 66.93%, but this team recently wins 78% of matches with these odds.
Form
✺ - easy match;
✺ - difficult match;
Latest Head to Head
| ATP Challenger | | | 13.05.25 | Juan Manuel Cerundolo - Federico Cina | 2:0 |
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Upcoming Matches
✺ - easy match;
✺ - difficult match;