Match Info
CHALLENGER MEN - SINGLES: Lexington, hard - 1/8-finalsDate: 31 July 2025, Thursday
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Rei Sakamoto |
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Eliot Spizzirri |
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- The best margin for this event is 4.8%, offered by

#Advertisement. For Live Stream GEO restrictions apply. Funded account required. GamblingTherapy.org. 18+ Current Win Probability
Rei Sakamoto 45.9% | Eliot Spizzirri 54.1% |
Initial Probability
(when we started the analysis)
Our Initial ML Estimation
Analysis of Changes in Winning Probabilities:
Rei Sakamoto has improved its chances compared to the initial analysis. (+0.8%)Eliot Spizzirri has seen a decrease in its chances compared to the initial analysis. (-0.8%)ML Model estimates a lower probability for Rei Sakamoto than the current prediction. (-3.5%)ML Model estimates a higher probability for Eliot Spizzirri than the current prediction. (+3.5%)Rei Sakamoto - Eliot Spizzirri Predictions
Verified Performance Core (Selected Experts): 1 Selected Experts predict this event. Spizzirri (votes: 1 - 100%).
Users Predictions:
Eliot Spizzirri will win
(5 of 6 users predict this - 83.33%).
Confidence interval (95%): 53.51% – 100%.Expected Score (Market Odds): 0:2 
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Preview
Sakamoto is ranked ATP: 205. Spizzirri is ranked ATP: 124.Recent performances by Sakamoto have been up and down (last 5 games: 3 wins).Spizzirri is showing top-class performance now (in the last 5 games, wins – 4).Sakamoto may have a physical advantage due to more rest days in recent times. The chances of victory for both players are nearly identical in this match. We predict that Spizzirri will win today's game, with odds of 1.7.In the last 1 head-to-head match, Sakamoto won 0 matches, drew 0 matches, lost 1 match, and goals 1:2.
Last Results with these Odds
Rei Sakamoto - the odds 2.09 are the expected chance of winning is 45.14%, but this team recently wins 71% of matches with these odds.
Form
✺ - easy match;
✺ - difficult match;
Latest Head to Head
| ATP Challenger | | | 22.07.25 | Eliot Spizzirri - Rei Sakamoto | 2:1 |
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Upcoming Matches
✺ - easy match;
✺ - difficult match;